Sort Names by First Name

Names are stored in the pattern last name first pattern [lastName, firstName].

For example given the name “Sharma, Rakesh”, “Rakesh” is first name and “Sharma” is last name.

Complete the method provided to return the collection of strings sorted based on their first name.

Method:

public static String[ ] SortByFirstName(string[ ] names)
{ 
   // code here 
}

Sample Input & Output: 

UTC	Sample Input	Sample Output
01	“Sharma, Rakesh”, “Patil, Parthiv”, “Gowda, Anil”, “Prasad, Vishnu”, “Khan, Amir”	“Khan, Amir”, “Gowda, Anil”, “Patil, Parthiv”, “Sharma, Rakesh”, “Prasad, Vishnu”
02	“Krishna, Gopal”, “Page, Larry”, “King, Gavin”, “Swamy, Krishna”	“King, Gavin” , “Krishna, Gopal”, “Swamy, Krish-na”, “Page, Larry”

SOLUTION: 

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace SortNamesbyFirstName_DEP
{
    class Program
    {
        static void Main(string[] args)
        {
            Console.WriteLine("Enter the number of element to be enter : ");
            int no = int.Parse(Console.ReadLine());
            String[] names = new String[no];
            Console.WriteLine("Enter " + no + " name with surname seprated with \",\" ");
            for (int i = 0; i < no; i++)
            {
                names[i] = Console.ReadLine();
            }
            names = SortByFirstName(names);
            Console.WriteLine("\n\nName after sorted is : \n\n");
            foreach (String item in names)
            {
                Console.WriteLine(item);
            }
            Console.Read();
        }

        public static String[] SortByFirstName(string[] names)
        {
            Array.Sort(names, delegate(string str, string str1)
            {
                string fstName1, fstName2;
                fstName1 = str.Substring(str.IndexOf(','), str.Length - str.IndexOf(','));
                fstName2 = str1.Substring(str1.IndexOf(','), str1.Length - str1.IndexOf(','));
                return fstName1.CompareTo(fstName2) > 0 ? 1 : -1;
            });
            return names;
        }
    }
}