Armstrong number

Write a program to check given number is armstrong or not.

SOLUTION:

 /*
 * Program for checking Armstrong number 
 * Written by Shaeed Khan. 
 * Date: 04 Aug 2014
 * Version- 1.0 
 * Language: C
 */

#include < stdio.h >  
#include < stdlib.h > 

void main()
{
 int n,x;
 printf("Enter a number:");
 scanf("%d",&n);
 x=armstrong(n);
 if(x==n)
  printf("Arm strong");
 else
  printf("Not arm strong");
}

int armstrong(int num)
{
 int sum=0,r;
 while(num!=0)
 {
  r=num%10;
  num=num/10;
  sum=sum+(r*r*r);
 }
 return sum;
}